如题所述
第1个回答 2019-06-06
1.f(-x)=loga[-x+√(x^2+1)]=loga[1/(x+√(x^2+1))]=-loga[x+√(x^2+1)]=-f(x)
所以f(x)为奇函数,选b
2.lim(x趋于正无穷)arctanx=π/2
lim(x趋于负无穷)arctanx=-π/2
则极限不存在,但有界,d
3.limx[ln(x-1)-lnx]=limxln(1-1/x)=limx(-1/x)=-1,选b
4.原式=limsinx^2/(4x^3)=limx^2/(4x^3)=lim1/(4x)=无穷,题目打错了吧
所以f(x)为奇函数,选b
2.lim(x趋于正无穷)arctanx=π/2
lim(x趋于负无穷)arctanx=-π/2
则极限不存在,但有界,d
3.limx[ln(x-1)-lnx]=limxln(1-1/x)=limx(-1/x)=-1,选b
4.原式=limsinx^2/(4x^3)=limx^2/(4x^3)=lim1/(4x)=无穷,题目打错了吧