如题所述
第1个回答 推荐于2016-12-02
解：原式=【(x^2-2x+1)/(x^2-1)】^2÷【(x^2-x)/(x+1)】^2
=【(x-1)^2/(x+1)(x-1)】^2÷【x(x-1)/(x+1)】^2
=(x-1)^2/(x+1)^2*(x+1)^2/x^2(x-1)^2
=1/x^2本回答被提问者和网友采纳
=【(x-1)^2/(x+1)(x-1)】^2÷【x(x-1)/(x+1)】^2
=(x-1)^2/(x+1)^2*(x+1)^2/x^2(x-1)^2
=1/x^2本回答被提问者和网友采纳
