如题所述
第1个回答 2011-02-26
(sinX求导*linX)+(sinx*linx的导数)=cosx*linx+sinx*1/X
第2个回答 2011-02-26
y = (sinx)^lnx
lny = (lnx) ln(sinx)
(1/y) y' = (lnx) (1/sinx) cosx + (ln(sinx)) 1/x
= (lnx) cotx + (1/x) lin(sinx)
y' = [(lnx) cotx + (1/x) lin(sinx)]y
= [(lnx) cotx + (1/x) lin(sinx)]((lnx) cotx + (1/x) lin(sinx))追问
lny = (lnx) ln(sinx)
(1/y) y' = (lnx) (1/sinx) cosx + (ln(sinx)) 1/x
= (lnx) cotx + (1/x) lin(sinx)
y' = [(lnx) cotx + (1/x) lin(sinx)]y
= [(lnx) cotx + (1/x) lin(sinx)]((lnx) cotx + (1/x) lin(sinx))追问
y=x根号下(1-x)/(1+x) y=(x^2/1-x)*根号下(5-x)/(3+x)^2
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