如题所述
第1个回答 推荐于2016-06-07
$atime = '';
$ttime = stringtotime('doday');
if($atime >= $ttime){echo '今天';}
elseif($atime >= $ttime-86400 and $atime<$ttime){echo '昨天';}
else{echo '不是这两天';}本回答被提问者采纳
$ttime = stringtotime('doday');
if($atime >= $ttime){echo '今天';}
elseif($atime >= $ttime-86400 and $atime<$ttime){echo '昨天';}
else{echo '不是这两天';}本回答被提问者采纳
