输出结果
应该是这个图片，第一张传错了
第1个回答 2015-03-19
把你的sql语句这样写试试~~
$sql = "insert into
adminU( uId, uUser, uPassword, uName, uCompany, uTel, uFax, uEmail, uRegTime )
VALUES ('',
'" . $_POST[uUser] . "',
'" . $pwd . "',
'" . $_POST[uName] . "',
'" . $_POST[uCompany] . "',
'" . $_POST[uTel] . "',
'" . $_POST[uFax] . "',
'" . $_POST[uEmail] . "',
now())";
echo $sql;本回答被提问者和网友采纳
$sql = "insert into
adminU( uId, uUser, uPassword, uName, uCompany, uTel, uFax, uEmail, uRegTime )
VALUES ('',
'" . $_POST[uUser] . "',
'" . $pwd . "',
'" . $_POST[uName] . "',
'" . $_POST[uCompany] . "',
'" . $_POST[uTel] . "',
'" . $_POST[uFax] . "',
'" . $_POST[uEmail] . "',
now())";
echo $sql;本回答被提问者和网友采纳
第2个回答 2015-03-19
没有链接数据库追问
在开头链接了，只是没有截开头的而已
