购买某物品时，若所花的钱x在下述范围内，则可以按对应折扣支付y:
x x<1000
0.9x 1000≤x<2000
0.8x 2000≤x<3000
0.7x x.≥3000
y=
求高手指点
第1个回答 2014-02-02
#include<iostream>
using namespace std;
int main()
{
int x;
int y;
cin >> x;
switch(x/1000)
{
case 0:
cout << " y = " << x << endl;
break;
case 1:
cout << " y = " << 0.9*x << endl;
break;
case 2:
cout << " y = " << 0.8*x << endl;
break;
case 3:
cout << " y = " << 0.7*x << endl;
break;
}
}本回答被提问者和网友采纳
using namespace std;
int main()
{
int x;
int y;
cin >> x;
switch(x/1000)
{
case 0:
cout << " y = " << x << endl;
break;
case 1:
cout << " y = " << 0.9*x << endl;
break;
case 2:
cout << " y = " << 0.8*x << endl;
break;
case 3:
cout << " y = " << 0.7*x << endl;
break;
}
}本回答被提问者和网友采纳
第2个回答 2014-02-02
利用C语言整形数 除法的特性
switch(x/1000)
{
case 0:
//
break;
case 1:
//
break;
case 2:
//
break;
default:
//
break;
}
switch(x/1000)
{
case 0:
//
break;
case 1:
//
break;
case 2:
//
break;
default:
//
break;
}
