编一函数：判别某一年是否为闰年，若是，返回值为1，否则返回值为0。

#include int leaping(int year); void main() { int year,loop; printf("input year:"); scanf("%d",&year); loop = leaping(year); if(loop) printf("%d is ",year); else printf("%d is not ",year); printf("a leap year\n"); } int leaping(int year) { if(year%400==0)return 1; else if(year%4==0&&year%100!=0) return 1; else return 0; }本回答被网友采纳