如何向sql数据库中存取照片

如题所述

第1个回答  2022-09-29
分类: 电脑/网络 >> 程序设计 >> 其他编程语言
解析:

的:

private void btnUpload_Click(object sender, System.EventArgs e)

{

得到用户要上传的文件名

string strFilePathName = loFile.PostedFile.FileName;

string strFileName = Path.GetFileName(strFilePathName);

int FileLength = loFile.PostedFile.ContentLength;

if(FileLength<=0)

return;

try

{上传文件

Byte[] FileByteArray = new Byte[FileLength]; 图象文件临时储存Byte数组

Stream StreamObject = loFile.PostedFile.InputStream; 建立数据流对像

读取图象文件数据,FileByteArray为数据储存体,0为数据指针位置、FileLnegth为数据长度

StreamObject.Read(FileByteArray,0,FileLength);

建立SQL Server链接

string strCon = System.Configuration.ConfigurationSettings.AppSettings["DSN"];

SqlConnection Con = new SqlConnection(strCon);

String SqlCmd = "INSERT INTO ImageStore (ImageData, ImageContentType, ImageDescription, ImageSize) VALUES (@Image, @ContentType, @ImageDescription, @ImageSize)";

SqlCommand CmdObj = new SqlCommand(SqlCmd, Con);

CmdObj.Parameters.Add("@Image",SqlDbType.Binary, FileLength).Value = FileByteArray;

CmdObj.Parameters.Add("@ContentType", SqlDbType.VarChar,50).Value = loFile.PostedFile.ContentType; 记录文件类型

把其它单表数据记录上传

CmdObj.Parameters.Add("@ImageDescription", SqlDbType.VarChar,200).Value = tbDescription.Text;

记录文件长度,读取时使用

CmdObj.Parameters.Add("@ImageSize", SqlDbType.BigInt,8).Value = FileLength;

Con.Open();

CmdObj.ExecuteNonQuery();

Con.Close();

跳转页面

Response.Redirect("ShowAllx");

}

catch

{

}

}

2.DataGrid控件绑定数据

程序代码

private void Page_Load(object sender, System.EventArgs e)

{

string strCon = System.Configuration.ConfigurationSettings.AppSettings["DSN"];

SqlConnection con = new SqlConnection(strCon);

SqlDataAdapter da = new SqlDataAdapter("Select * from ImageStore",con);

DataSet ds = new DataSet();

da.Fill(ds,"image");

dgShow.DataSource = ds.Tables["image"].DefaultView;

dgShow.DataBind();

}

3.显示数据库图片数据

程序代码

private void Page_Load(object sender, System.EventArgs e)

{

int ImgID = Convert.ToInt32(Request.QueryString["ID"]); ID为图片ID

建立数据库链接

string strCon = System.Configuration.ConfigurationSettings.AppSettings["DSN"];

SqlConnection Con = new SqlConnection(strCon);

String SqlCmd = "SELECT * FROM ImageStore WHERE ImageID = @ImageID";

SqlCommand CmdObj = new SqlCommand(SqlCmd, Con);

CmdObj.Parameters.Add("@ImageID", SqlDbType.Int).Value = ImgID;

Con.Open();

SqlDataReader SqlReader = CmdObj.ExecuteReader();

SqlReader.Read();

Response.ContentType = (string)SqlReader["ImageContentType"];设定输出文件类型

输出图象文件二进制数制

Response.OutputStream.Write((byte[])SqlReader["ImageData"], 0, (int)SqlReader["ImageSize"]);

Response.End();

也可以保存为图像

FileStream fs = new FileStream(@"C:\aa.BMP", FileMode.OpenOrCreate, FileAccess.Write);

fs.Write((byte[])SqlReader["ImageData"], 0,(int)SqlReader["ImageSize"]);

fs.Close();

Con.Close();

}

asp的:

ASP图片存入数据库源程序

写图片到数据库:<%

response.buffer=true

formsize=request.totalbytes

formdata=request.binaryread(formsize)

bncrlf=chrB(13) & chrB(10)

divider=leftB(formdata,clng(instrb(formdata,bncrlf))-1)

datastart=instrb(formdata,bncrlf & bncrlf)+4

dataend=instrb(datastart+1,formdata,divider)-datastart

mydata=midb(formdata,datastart,dataend)

Dim Conn

Set Conn=Server.CreateObject("adodb.connection")

Conn.Open strConn

set rec=server.createobject("ADODB.recordset")

rec.Open "SELECT * FROM images order by id desc",Conn,1,3

rec.addnew

rec("images").appendchunk mydata

rec.update

rec.close

set rec=nothing

set connGraph=nothing

%>

从数据库读图片:

<%

Dim Conn

Set Conn=Server.CreateObject("adodb.connection")

Conn.Open strConn

set rec=server.createobject("ADODB.recordset")

strsql="select images from images where id=" & trim(request("id"))

rec.open strsql,Conn,1,1

Response.ContentType = "img/*"

Response.BinaryWrite rec("images").getChunk(7500000)

%>

注:图片存数据库是以二进制存的,在读写图片时文本和图片只能分开保存。

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