如题所述
第1个回答 2024-01-11
这是条件概率.
P(B|A上横杠)=P(BA上横杠)/P(A上横杠)
=[P(B)-P(BA)]/P(A上横杠)
=(0.4-0)/0.7
=4/7,5,P(B|A上横杠)=P(B∩A上横杠)/P(A上横杠)
根据贝叶斯定理,P(B)=P(B∩A上横杠)+P(B∩A)
因为AB不相容,P(B∩A)=0,P(B∩A上横杠)=0.4
所以P(B|A上横杠)=4/7,2,6/7
P(AB)=0,P(A)=0.3,P(B^)=0.6
A^B=B-AB
P(A^B)=P(B)-P(AB)=0.6-0=0.6
所以P(B|A^)=0.6/0.7,1,P(B/A上横杠)=P(BA上横杠)P(A上横杠)
=[P(B-P(AB)]P(A上横杠)
=(0.4-0)/0.7
=4/7,1,
P(B|A上横杠)=P(BA上横杠)/P(A上横杠)
=[P(B)-P(BA)]/P(A上横杠)
=(0.4-0)/0.7
=4/7,5,P(B|A上横杠)=P(B∩A上横杠)/P(A上横杠)
根据贝叶斯定理,P(B)=P(B∩A上横杠)+P(B∩A)
因为AB不相容,P(B∩A)=0,P(B∩A上横杠)=0.4
所以P(B|A上横杠)=4/7,2,6/7
P(AB)=0,P(A)=0.3,P(B^)=0.6
A^B=B-AB
P(A^B)=P(B)-P(AB)=0.6-0=0.6
所以P(B|A^)=0.6/0.7,1,P(B/A上横杠)=P(BA上横杠)P(A上横杠)
=[P(B-P(AB)]P(A上横杠)
=(0.4-0)/0.7
=4/7,1,