matlab计算一个函数在多个点的值程序结果为什么是这样？自变量和变量都是数组

程序
for i=1:11
x(i)=cos((23-2*i)*pi/22);
y(i)=1/(1+x(i).^2);
fprintf('y(%f)=%f\n',x,y);
end
结果为什么不是11个点的值，而是下面的计算结果，至少有30个值。
y(-0.989821)=0.505115
y(-0.989821)=-0.909632
y(0.505115)=0.547216
y(-0.989821)=-0.909632
y(-0.755750)=0.505115
y(0.547216)=0.636473
y(-0.989821)=-0.909632
y(-0.755750)=-0.540641
y(0.505115)=0.547216
y(0.636473)=0.773819
y(-0.989821)=-0.909632
y(-0.755750)=-0.540641
y(-0.281733)=0.505115
y(0.547216)=0.636473
y(0.773819)=0.926464
y(-0.989821)=-0.909632
y(-0.755750)=-0.540641
y(-0.281733)=0.000000
y(0.505115)=0.547216
y(0.636473)=0.773819
y(0.926464)=1.000000
y(-0.989821)=-0.909632
y(-0.755750)=-0.540641
y(-0.281733)=0.000000
y(0.281733)=0.505115
y(0.547216)=0.636473
y(0.773819)=0.926464
y(1.000000)=0.926464
y(-0.989821)=-0.909632
y(-0.755750)=-0.540641
y(-0.281733)=0.000000
y(0.281733)=0.540641
y(0.505115)=0.547216
y(0.636473)=0.773819
y(0.926464)=1.000000

相关了解……