sql语句查询结果只取从第m条开始到第n条结束请问该怎么做

取n到m行

1.
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)

2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc

3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc

4.如果tablename里没有其他identity列，那么：
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename

取n到m条的语句为：
select * from #temp where id0 > =n and id0 <= m

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行：
exec sp_dboption 你的DB名字,'select into/bulkcopy',true

5.如果表里有identity属性，那么简单：
select * from tablename where identity_col between n and m

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

什么数据库?不同数据的sql是不同的.
mysql,postgresql用limit和offset.
sql server 用两次top.
firebird用rows.
其它的我不知道.本回答被提问者采纳

oracle的话语法如下

1.如果需要id排序
select * from (
select t.* , rownum as seq from (
select * from yourTable
order by id )t)
where seq>= m and seq<= n ;

2.如果不需要id排序
select *
from (select t.*, rownum as seq from yourTable t)
where seq >= m
and seq <= n

SELECT TOP n-m+1 * FROM 表名 WHERE (id NOT IN (SELECT TOP m-1 id FROM 表名))本回答被网友采纳

select * from table limit m , (n-m);