<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>新建网页</title>
</head>
<input type="text" name="a1" id="txt" value="3,5,6,7,10," size="10"/>
<input type="text" name="a2" id="txt0" value="5" size="3"/><body>
</body></html>
第1个回答 推荐于2016-06-30
提供三个方法,具体代码如下:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>新建网页</title>
</head><body>
<input type="text" name="a1" id="txt" value="3,5,6,7,10," size="10"/>
<input type="text" name="a2" id="txt0" value="5" size="3"/>
<script>
function showAns(){
var listA = document.getElementById("txt").value;
var listB = document.getElementById("txt0").value;
var isBigger = checkIsBigger(listA.split(","),listB.split(",")); //方法1
//var isBigger = checkIsBigger2(listA.split(","),listB.split(","));//方法2
//var isBigger = checkIsBigger3(listA.split(","),listB.split(","));//方法3
if(isBigger){
alert("A1中有数字比A2的大");
}
}
/** 方法1, 遍历比较, 找到一个就返回true **/
function checkIsBigger(listA, listB){
var ans = false;
var lengthA = listA.length;
var lengthB = listB.length;
for(var i=0;i<lengthA;i++){
var curA = parseInt(listA[i]);
for(var j=0;j<lengthB;j++){
var curB = parseInt(listB[i]);
if(curA > curB){
return true;
}
}
}
return true;
}
/** 方法2, A的最大值大于B的最小值 找到一个就返回true, 转化成数字 **/
function checkIsBigger2(listA, listB){
var maxA = parseInt(listA[0],10);
for(var i=1;i<listA.length;i++){
var cur = parseInt(listA[i],10);
if(maxA < cur){
maxA = cur;
}
}
var minB = parseInt(listB[0],10);
for(var i=1;i<listB.length;i++){
var cur = parseInt(listB[i],10);
if(minB > cur){
minB = cur;
}
}
return maxA > minB;
}
/** 方法3, 使用数组的some方法,新版本的浏览器环境支持**/
function checkIsBigger3(listA, listB){
var listA_number = listA.map(function(x){return parseInt(x,10);});
var listB_number = listB.map(function(x){return parseInt(x,10);});
return listA_number.some(function(x){return listB_number.some(function(y){return x>y})});
}
showAns();
</script>
</body></html>本回答被提问者和网友采纳
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>新建网页</title>
</head><body>
<input type="text" name="a1" id="txt" value="3,5,6,7,10," size="10"/>
<input type="text" name="a2" id="txt0" value="5" size="3"/>
<script>
function showAns(){
var listA = document.getElementById("txt").value;
var listB = document.getElementById("txt0").value;
var isBigger = checkIsBigger(listA.split(","),listB.split(",")); //方法1
//var isBigger = checkIsBigger2(listA.split(","),listB.split(","));//方法2
//var isBigger = checkIsBigger3(listA.split(","),listB.split(","));//方法3
if(isBigger){
alert("A1中有数字比A2的大");
}
}
/** 方法1, 遍历比较, 找到一个就返回true **/
function checkIsBigger(listA, listB){
var ans = false;
var lengthA = listA.length;
var lengthB = listB.length;
for(var i=0;i<lengthA;i++){
var curA = parseInt(listA[i]);
for(var j=0;j<lengthB;j++){
var curB = parseInt(listB[i]);
if(curA > curB){
return true;
}
}
}
return true;
}
/** 方法2, A的最大值大于B的最小值 找到一个就返回true, 转化成数字 **/
function checkIsBigger2(listA, listB){
var maxA = parseInt(listA[0],10);
for(var i=1;i<listA.length;i++){
var cur = parseInt(listA[i],10);
if(maxA < cur){
maxA = cur;
}
}
var minB = parseInt(listB[0],10);
for(var i=1;i<listB.length;i++){
var cur = parseInt(listB[i],10);
if(minB > cur){
minB = cur;
}
}
return maxA > minB;
}
/** 方法3, 使用数组的some方法,新版本的浏览器环境支持**/
function checkIsBigger3(listA, listB){
var listA_number = listA.map(function(x){return parseInt(x,10);});
var listB_number = listB.map(function(x){return parseInt(x,10);});
return listA_number.some(function(x){return listB_number.some(function(y){return x>y})});
}
showAns();
</script>
</body></html>本回答被提问者和网友采纳
