在一个方法中抛出自定义异常,如何在该方法的catch处理程序中捕获并重新抛出
第1个回答 推荐于2019-10-19
public class sssss {
public static void main(String[] args) {
System.out.print("Please input an Integer: ");
int value = new Scanner(System.in).nextInt();
try{
if(value < 0){
throw new MyException("My Exception comes!");
}
}catch (MyException myExp){
System.out.println("MyExcepton caugth!");
}
}
}
class MyException extends Exception{
public MyException(String s){
System.out.println("MyException occurs. The value must be greater than ZERO!");
}
}
-----------------------
Please input an Integer: -5
MyException occurs. The value must be greater than ZERO!
MyExcepton caugth!本回答被网友采纳
public static void main(String[] args) {
System.out.print("Please input an Integer: ");
int value = new Scanner(System.in).nextInt();
try{
if(value < 0){
throw new MyException("My Exception comes!");
}
}catch (MyException myExp){
System.out.println("MyExcepton caugth!");
}
}
}
class MyException extends Exception{
public MyException(String s){
System.out.println("MyException occurs. The value must be greater than ZERO!");
}
}
-----------------------
Please input an Integer: -5
MyException occurs. The value must be greater than ZERO!
MyExcepton caugth!本回答被网友采纳