分别使用for循环、while循环和do…while循环三种循环语句编写程序，输出九九乘法口诀表，显示效果如下：
1*1= 1 1*2= 2 1*3= 3 1*4= 4 1*5= 5 1*6= 6 1*7= 7 1*8= 8 1*9= 9
2*2= 4 2*3= 6 2*4= 8 2*5=10 2*6=12 2*7=14 2*8=16 2*9=18
3*3= 9 3*4=12 3*5=15 3*6=18 3*7=21 3*8=24 3*9=27
4*4=16 4*5=20 4*6=24 4*7=28 4*8=32 4*9=36
5*5=25 5*6=30 5*7=35 5*8=40 5*9=45
6*6=36 6*7=42 6*8=48 6*9=54
7*7=49 7*8=56 7*9=63
8*8=64 8*9=72
9*9=81
要求将三种循环语句的编程写在一个程序中。怎么做
第1个回答 推荐于2018-03-11
//---------------------------------------------------------------------------
#pragma hdrstop
#include <stdio.h>
#include <conio.h>
//---------------------------------------------------------------------------
#pragma argsused
int main(int argc, char* argv[])
{
printf("\n\nfor:\n");
for (int i=1;i<=9;i++)
{
for (int k=i;k<=9;k++)
printf("%d*%d=%d ",i,k,i*k);
printf("\n");
}
printf("\n\nwhile:\n");
int i=1;
while (i<=9)
{
int k=i;
while (k<=9)
{
printf("%d*%d=%d ",i,k,i*k);
k++;
}
i++;
printf("\n");
}
printf("\n\ndo...while:\n");
i=1;
do
{
int k=i;
do
{
printf("%d*%d=%d ",i,k,i*k);
k++;
} while (k<=9);
i++;
printf("\n");
} while (i<=9);
getch();
return 0;
}
//---------------------------------------------------------------------------本回答被提问者和网友采纳
#pragma hdrstop
#include <stdio.h>
#include <conio.h>
//---------------------------------------------------------------------------
#pragma argsused
int main(int argc, char* argv[])
{
printf("\n\nfor:\n");
for (int i=1;i<=9;i++)
{
for (int k=i;k<=9;k++)
printf("%d*%d=%d ",i,k,i*k);
printf("\n");
}
printf("\n\nwhile:\n");
int i=1;
while (i<=9)
{
int k=i;
while (k<=9)
{
printf("%d*%d=%d ",i,k,i*k);
k++;
}
i++;
printf("\n");
}
printf("\n\ndo...while:\n");
i=1;
do
{
int k=i;
do
{
printf("%d*%d=%d ",i,k,i*k);
k++;
} while (k<=9);
i++;
printf("\n");
} while (i<=9);
getch();
return 0;
}
//---------------------------------------------------------------------------本回答被提问者和网友采纳
