//用户信息数据结构
typedef struct
{
long number; //用户编号 6位
char name[20]; //用户名
char password[8]; //用户密码
int power; //权限判断 1 为管理员2为普通用户
}user;
user yh[100]={100000,"gavin","gavine",1,100001,"wnag","wangf",2};
密码验证后，让这个结构体里的gavin为管理员，及返回值为1，wang为普通用户，即反值为2；
第1个回答 2009-05-31
#include <stdio.h>
#include <string.h>
typedef struct
{
long number; //用户编号 6位
char name[20]; //用户名
char password[8]; //用户密码
int power; //权限判断 1 为管理员2为普通用户
} user;
user yh[100]={100000,"gavin","gavine",1,100001,"wnag","wangf",2};
int length = 2;
int checkuser(long num, const char *nm, const char *pwd)
{
int i;
for (i = 0; i < length; ++i)
{
if (yh[i].number == num && !strcmp(yh[i].name, nm) && !strcmp(yh[i].password, pwd))
{
if (1==yh[i].power)
return 1;
else
return 2;
}
}
}
void main()
{
printf("%d\n", checkuser(100000, "gavin", "gavine"));
}本回答被提问者采纳
#include <string.h>
typedef struct
{
long number; //用户编号 6位
char name[20]; //用户名
char password[8]; //用户密码
int power; //权限判断 1 为管理员2为普通用户
} user;
user yh[100]={100000,"gavin","gavine",1,100001,"wnag","wangf",2};
int length = 2;
int checkuser(long num, const char *nm, const char *pwd)
{
int i;
for (i = 0; i < length; ++i)
{
if (yh[i].number == num && !strcmp(yh[i].name, nm) && !strcmp(yh[i].password, pwd))
{
if (1==yh[i].power)
return 1;
else
return 2;
}
}
}
void main()
{
printf("%d\n", checkuser(100000, "gavin", "gavine"));
}本回答被提问者采纳
