如题所述
第1个回答 2022-07-09
含碳0.6%的铁碳合金室温组织是铁素体+珠光体,根据杠杆定律可得:
WF=(0.77-0.6)/(0.77-0.0218)=0.17/0.7482=0.2272=22.72%
WP=1-WF=1-0.2272=0.7728=77.28%
可知:铁素体占22.72%,珠光体占77.28%.
WF=(0.77-0.6)/(0.77-0.0218)=0.17/0.7482=0.2272=22.72%
WP=1-WF=1-0.2272=0.7728=77.28%
可知:铁素体占22.72%,珠光体占77.28%.