设计一个函数,要用到void reverse(int a[ ],int n) 颠倒数组a的前n个...答:include<iostream> using namespace std;void reverse(int *a,int n){ int i,t;for(i=0;i<n/2;i++){ t=*(a+i);(a+i)=*(a+n-i-1);(a+n-i-1)=t;} } int main(){ int i,a[]={0,1,2,3,4,5,6,7,8,9};reverse(a,10);for(i=0;i<10;i++)cout<<a[i]<...