请问怎么用C语言统计一个数组中不同元素它们重复的个数啊?答:public static void main(String[] args) { // 测试数据:总共是9个不同的元素,按照升序排好,其中有重复出现的元素。int[] array = new int[] { 1, 1, 2, 2, 2, 3, 4, 5, 5, 6, 7, 7, 8, 9 };System.out.println(new Test().count(array));} } ...
C语言中,寻找两个数组中相同的元素的个数,与元素答:80,70,60,50,40,772,294,1065,184}; //10int a[]={90,80,70,60,50,40,30,20,10,9,8,7,6,5,42,40,50,1,2,3}; //在这里定义的好处是,可以在任意函数中通用 20int _tmain(int argc, _TCHAR* argv[]){ int i; int c[sizeof(b)/sizeof(b[0])...
C语言 有3个数a,b,c,要求按大小顺序把它们输出。答:printf("%d %d %d\n",a,b,c);return 0;} 2.用数组求解:include<stdio.h> int main(){ int a,b,c,t;printf("请输入三个整数:\n");scanf("%d\t%d\t%d", &a, &b, &c);if (a > b){ t = a;a = b;b = t;} if (a > c){ t = a;a = c;c = t;} if (...