c语言编写一个程序,实现一个3×4矩阵转置。答:思路:定了两个二维数组分别存储转置前后的矩阵,接着for循环依次转置即可。//参考代码#include<stdio.h> int main() { int a[3][4]={{1,2,3,4},{5,6,7,8},{9,10,11,12}},b[4][3]; int i,j; for(i=0;i<3;i++) for(j=0;j<4;j++) b[j][i]=a[i][j]; for(...
C语言编程实现,将4*4阶矩阵转置答:void trans( int *p, int n){ int i,j,t;for(j=0;j<n;j++){ for(i=j+1;i<n;i++){ t = p[j*n+i];p[j*n+i] = p[i*n+j];p[i*n+j] = t;};};} main() { int p[4][4]= {{1,2,3,4},{5,6,7,8},{9,10,11,12},{13,14,15,16}},i,j;p...
c语言如何通过定义函数来转置矩阵?答:int main(){ struct aaa { int x;int y;};struct aaa t,a[3][3]= {0,0,0,1,0,2,1,0,1,1,1,2,2,0,2,1,2,2};int i,j;for(i=0; i<3; i++){ for(j=0; j<3; j++)printf("[%d,%d] ",a[i][j].x,a[i][j].y);printf("\n");} printf("after:\n...
...将其转置后,变成4行3列的矩阵输出。这个c语言的代码咋写答:int main(void){ int a[3][4] = {11,12,13,14,21,22,23,24,31,32,33,34};int b[4][3];int i, j;for(i=0; i<4; i++) //转置数组;for(j=0; j<3; j++)b[i][j] = a[j][i];for(i=3; i>=0; i--) //反向输出转置后的数组;{ for(j=2; j>=0; j-...