写一个c语言程序(输入两个复数(格式如2+3i),输出两个复数相加的结果...答:include<stdio.h> int main(){ int x1,y1, x2, y2;printf("Please input complex 1:");scanf("%d+%di", &x1, &y1);printf("Please input complex 2:");scanf("%d+%di", &x2, &y2);printf("The sum is=%d+%di\n", x1+x2, y1+y2);return 0;} 以上程序是最简单的形式...
已知a,b,c是复数,(a-b)^2 +(b-c)^2 +(c-a)^2=0 是a=b=c 的什么条件?答:是必要条件不是充分条件.由a=b=c,可得(a-b)^2 +(b-c)^2 +(c-a)^2=0,故(a-b)^2 +(b-c)^2 +(c-a)^2=0是a=b=c的必要条件.取a=0,b=1,c=(1+i√3)/2,(a-b)^2 +(b-c)^2 +(c-a)^2=1+((1-i√3)/2)^2 +((1+i√3)/2)^2=0 但a,b,c互不等于...