编程求菲波那挈数列1,1,2,3,5,8,13,21,...的前n项,n由用户输入要求使用...答:int i,n;//int sum=0;printf("输入(n<30)n=");scanf("%d",&n);a[0]=1;a[1]=1;for(i=2;i<n;i++)a[i]=a[i-1]+a[i-2];for(i=0;i<n;i++){ printf("%4d",a[i]);if((i+1)%5==0) printf("\n");//sum=sum+a[i];} //printf("前%d项和为%d",n...