如题所述
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public int sum(int start, int end)
{
int sum = (start + end)*(end - start + 1)/2;
return sum;
}
public float sum(float start, float end)
{
float sum = (start + end)*(end - start + 1.0)/2.0;
return sum;
}
public int sum(int start, int end)
{
int sum = (start + end)*(end - start + 1)/2;
return sum;
}
public float sum(float start, float end)
{
float sum = (start + end)*(end - start + 1.0)/2.0;
return sum;
}
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第1个回答 2012-10-11
在一个类里写两个同名的求和方法,一个参数是整型,一个参数是浮点型