好像需要讨论x,y的取值范围
解ï¼
â[x/y]+â[y/x]
=[(âx)/(ây)]+[(ây)/(âx)]
=[(âx)(âx)/â(xy)]+[(ây)(ây)/â(xy)]
=(x+y)/â(xy)
=-5/â2
=(-5â2)/2
â[x/y]+â[y/x]
=[(âx)/(ây)]+[(ây)/(âx)]
=[(âx)(âx)/â(xy)]+[(ây)(ây)/â(xy)]
=(x+y)/â(xy)
=-5/â2
=(-5â2)/2
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