如题所述
(1/3-1/2)÷(1/4-1/3)Ã(1/5-1/4)÷(1/6-1/5)Ã(1/7-1/6)÷(1/8-1/7)
=[(1/3-1/2)Ã(1/5-1/4)Ã(1/7-1/6)]/[(1/4-1/3)Ã(1/6-1/5)Ã(1/8-1/7)]
=[(1/2-1/3)Ã(1/4-1/5)Ã(1/6-1/7)]/[(1/3-1/4)Ã(1/5-1/6)Ã(1/7-1/8)]
=[(1/(2Ã3))Ã(1/(4Ã5))Ã(1/(6Ã7))]/[(1/(3Ã4))Ã(1/(5Ã6))Ã(1/(7Ã8))]
=[1/(2Ã3Ã4Ã5Ã6Ã7)]/[1/(3Ã4Ã5Ã6Ã7Ã8)]
=(3Ã4Ã5Ã6Ã7Ã8)/(2Ã3Ã4Ã5Ã6Ã7)
=4
=[(1/3-1/2)Ã(1/5-1/4)Ã(1/7-1/6)]/[(1/4-1/3)Ã(1/6-1/5)Ã(1/8-1/7)]
=[(1/2-1/3)Ã(1/4-1/5)Ã(1/6-1/7)]/[(1/3-1/4)Ã(1/5-1/6)Ã(1/7-1/8)]
=[(1/(2Ã3))Ã(1/(4Ã5))Ã(1/(6Ã7))]/[(1/(3Ã4))Ã(1/(5Ã6))Ã(1/(7Ã8))]
=[1/(2Ã3Ã4Ã5Ã6Ã7)]/[1/(3Ã4Ã5Ã6Ã7Ã8)]
=(3Ã4Ã5Ã6Ã7Ã8)/(2Ã3Ã4Ã5Ã6Ã7)
=4
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第1个回答 2012-11-16
原式=1/2*1/3*1/4*1/5*1/6*1/7/(1/3*1/4*1/5*1/6*1/7*1/8)=1/2/(1/8)=4