如何利用循环打印出如下效果？
实在是没有再好的办法了。
echo -n " "
for i in 1 3 5 7 10;do
for ((j=1;j<=$i;j++));do
echo -n "*";
done
echo
done
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第1个回答 2012-11-12
这个不知道是不是你要的效果，看你那图没什么规律啊：
[seesea2517 ~] $ ./a.sh 1
+
[seesea2517 ~] $ ./a.sh 2
+
+++
[seesea2517 ~] $ ./a.sh 3
+
+++
+++++
[seesea2517 ~] $ ./a.sh 4
+
+++
+++++
+++++++
[seesea2517 ~] $ cat a.sh
#!/bin/bash
if [ -z "$1" ]
then
echo "需要参数一，表示高度。"
exit
fi
for (( i = 1; i <= $1; ++i ))
do
line=""
for (( j = 0; j < 2 * i - 1; ++j ))
do
line="$line+"
done
echo "$line"
done
不知道你是不是截图不对，所以还有另一种效果：
[seesea2517 ~]$ ./a.sh 1
+
[seesea2517 ~]$ ./a.sh 2
+
+++
[seesea2517 ~]$ ./a.sh 3
+
+++
+++++
[seesea2517 ~]$ ./a.sh 6
+
+++
+++++
+++++++
+++++++++
+++++++++++
[seesea2517 ~]$ cat a.sh
#!/bin/bash
if [ -z "$1" ]
then
echo "需要参数一，表示高度。"
exit
fi
for (( i = 1; i <= $1; ++i ))
do
line=""
for (( j = $1; j >= i; --j ))
do
line="$line "
done
for (( j = 0; j < 2 * i - 1; ++j ))
do
line="$line+"
done
echo "$line"
done
[seesea2517 ~] $ ./a.sh 1
+
[seesea2517 ~] $ ./a.sh 2
+
+++
[seesea2517 ~] $ ./a.sh 3
+
+++
+++++
[seesea2517 ~] $ ./a.sh 4
+
+++
+++++
+++++++
[seesea2517 ~] $ cat a.sh
#!/bin/bash
if [ -z "$1" ]
then
echo "需要参数一，表示高度。"
exit
fi
for (( i = 1; i <= $1; ++i ))
do
line=""
for (( j = 0; j < 2 * i - 1; ++j ))
do
line="$line+"
done
echo "$line"
done
不知道你是不是截图不对，所以还有另一种效果：
[seesea2517 ~]$ ./a.sh 1
+
[seesea2517 ~]$ ./a.sh 2
+
+++
[seesea2517 ~]$ ./a.sh 3
+
+++
+++++
[seesea2517 ~]$ ./a.sh 6
+
+++
+++++
+++++++
+++++++++
+++++++++++
[seesea2517 ~]$ cat a.sh
#!/bin/bash
if [ -z "$1" ]
then
echo "需要参数一，表示高度。"
exit
fi
for (( i = 1; i <= $1; ++i ))
do
line=""
for (( j = $1; j >= i; --j ))
do
line="$line "
done
for (( j = 0; j < 2 * i - 1; ++j ))
do
line="$line+"
done
echo "$line"
done
