C语言中如何用循环实现十进制数转换成二进制数

#include<stdio.h>

main()
{
char *tentotwo(int n);

int num;

printf("please input a integer:");
scanf("%d",&num);
printf("该数转换为二进制为:%s\n\n", tentotwo(num));

}

char *tentotwo(int n)
{
int i,j=0;
int *p, *q, *f;
char *s;
p = (int *)malloc(32*sizeof(int));
s = (char *)malloc(32);
q = p;
f = (int *)malloc(32*sizeof(int));
while(n)
{
*q = n%2;
n /= 2;
q++;j++;
}
for(i=0;i<j;i++)
*(f+i)=*(p+j-1-i);
for(i=0;i<j;i++)
{
switch(*(f+i))
{
case 0 : *(s+i) = '0'; break;
case 1 : *(s+i) = '1'; break;
default : break;
}
}
*(s+j) = '\0';
return s;
}

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