如果a,b,c是三位数的三个数字，满足49a+7b+c=286,三位数100a+10b+c的结果是？

49A + 7B + C = 286

则7A + B = 40 + (6 - C)/7
要使(6 - C)/7为整数，显然C = 6

当C = 6时
7A + B = 40
则A = 6 - (2 + B)/7，显然B = 5，A = 5

三位数100a+10b+c = 556

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