编一个程序，用户先输入一个没有重复数字的三位数，比如说478，让程序来猜，每次猜完后，用户给出反馈，有几个数字正确，几个数字正确并且在正确的位置，直到程序猜对或者超过最大尝试次数。执行出来的结果如图。求大佬教，这个程序的大体结构是怎样的，怎么让程序随机产生没有重复数字的三位数，怎么根据用户的反馈来进行下一轮猜测。高悬赏！
# python 3.6+
from random import randint, choice
MAX = 5
def rd(h=3, repeat=False):
a = randint(1, 9)
choices = [i for i in range(0, 10) if i!=a]
ns = [a]
for i in range(h-1):
n = choice(choices)
ns.append(n)
choices = [i for i in choices if i!=n or repeat]
return ''.join([str(i) for i in ns])
def main():
answer = input('Please input a number: ')
for i in range(MAX):
n = rd()
q = input(f'{i+1}. Is {n} the right number?[y/(n)] ')
if q.strip() == 'y':
print('Done!')
return
print('Guess time reach limit. Exit!')
if __name__ == '__main__':
main()追问
n = input('Enter a number: ')
correct = len([i for i in n if i in str(answer)])
exact = len([a for a, b in zip(n, str(answer)) if a==b])
print(f'{correct} correct, {exact} exact.')
from random import randint, choice
MAX = 5
def rd(h=3, repeat=False):
a = randint(1, 9)
choices = [i for i in range(0, 10) if i!=a]
ns = [a]
for i in range(h-1):
n = choice(choices)
ns.append(n)
choices = [i for i in choices if i!=n or repeat]
return ''.join([str(i) for i in ns])
def main():
answer = input('Please input a number: ')
for i in range(MAX):
n = rd()
q = input(f'{i+1}. Is {n} the right number?[y/(n)] ')
if q.strip() == 'y':
print('Done!')
return
print('Guess time reach limit. Exit!')
if __name__ == '__main__':
main()追问
def rd(） 的部分看懂了，那怎么根据用户的反馈来进行猜数的调整呢？比如对于数字154，程序猜456，用户会反馈，2个数字correct，1个数字exact，然后程序需要根据这些信息来进行下一轮猜测。好复杂。。。非常感谢！
追答answer = 456n = input('Enter a number: ')
correct = len([i for i in n if i in str(answer)])
exact = len([a for a, b in zip(n, str(answer)) if a==b])
print(f'{correct} correct, {exact} exact.')
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