1/3x+30%x=1/2;3/5x-1/7=1

解： (3x3+4x2-5x+6)/(x2-3x+1) =(3x3-9x2+3x+13x2-39x+13+31x-7)/(x2-3x+1) =[3x(x2-3x+1)+13(x2-3x+1)+(31x-7)]/(x2-3x+1) =3x +13 + (31x-7)/(x2-3x+1) x2-3x+1除3x3+4x2-5x+6的商为3x+13，余式为31x-7

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