如题所述
/*功能：输入一个任意长度的正整数，求出它是几位数。*/
#include<stdio.h>
int main()
{
int number; int count = 0;//记录个数
scanf("%d", &number);
if (number == 0)
{
printf("number is %d\n",count+1);//0是一位数
} else
{
while (number != 0)
{
number = number / 10;
count++;
} printf("number is %d", count);
} return 0;
}
#include<stdio.h>
int main()
{
int number; int count = 0;//记录个数
scanf("%d", &number);
if (number == 0)
{
printf("number is %d\n",count+1);//0是一位数
} else
{
while (number != 0)
{
number = number / 10;
count++;
} printf("number is %d", count);
} return 0;
}
温馨提示：答案为网友推荐，仅供参考
第1个回答 2021-04-21
完整代码如下，仅供参考：
#include<stdio.h>
int main()
{
int n,count=0;
scanf("%d", &n);
if (n <= 0)
{
printf("必须输入");
return 1;
} else
{
while (n != 0)
{
n = n / 10;
count++;
}
printf("n是%d位数", count);
}
return 0;
}本回答被网友采纳
#include<stdio.h>
int main()
{
int n,count=0;
scanf("%d", &n);
if (n <= 0)
{
printf("必须输入");
return 1;
} else
{
while (n != 0)
{
n = n / 10;
count++;
}
printf("n是%d位数", count);
}
return 0;
}本回答被网友采纳
