请问这题怎么求导，详解。打勾的题。

=d{e^[-sin^2(1/x)]}
=e^[-sin^2(1/x)]*[-2sin(1/x)]*cos(1/x)*(-1/x²)
=e^[-sin^2(1/x)]2sin(1/x)cos(1/x)*(1/x²)
=e^[-sin^2(1/x)] *sin(2/x) *(1/x²)

y‘=-(e^(sin1/x)·cos(1/x))/x²