如题所述
递等式计算
99x48+99
=99×48+48+51
=(99+1)×48+51
=100×48+51
=4800+51
=4851
99x48+99
=99×48+48+51
=(99+1)×48+51
=100×48+51
=4800+51
=4851
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第1个回答 2017-04-06
99×48+99
=99×(48+1)
=99×49
=100×49-1×49
=4900-49
=4851
=99×(48+1)
=99×49
=100×49-1×49
=4900-49
=4851
第2个回答 2017-04-06
99x48+99
=99x(48+1)
=(100-1)x49
=4900-49
=4851
=99x(48+1)
=(100-1)x49
=4900-49
=4851
第3个回答 2017-04-06
=99×48+99×1
=99×(48+1)
=99×49
=(100-1)×49
=100×49-1×49
=4900-49
=4851
=99×(48+1)
=99×49
=(100-1)×49
=100×49-1×49
=4900-49
=4851
第4个回答 2017-04-06
99*48+99
=99*(48+1)
=99*49
=(100-1)*49
=100*49-1*49
=4900-49
=4851
=99*(48+1)
=99*49
=(100-1)*49
=100*49-1*49
=4900-49
=4851