如题所述
是说飞机开到Ankara,路程是765miles(英里),开去的时候顺风开,用了9小时,开回来的时候逆风开,用了17小时,求飞机的速度和风速。
先设机速为x,风速为y,则由题知:开去时:9*(x+y)=765 所以x+y=85;
开回来时:17(x-y)=765 所以x-y=45,即y=x-45;
得出:x+y=x-45+x=2x-45=85,所以2x=85+45=130,求出x=65,y=20
即the speed of the plane in still air is 65 miles an hour;the speed of the wind is 20 miles an hour
先设机速为x,风速为y,则由题知:开去时:9*(x+y)=765 所以x+y=85;
开回来时:17(x-y)=765 所以x-y=45,即y=x-45;
得出:x+y=x-45+x=2x-45=85,所以2x=85+45=130,求出x=65,y=20
即the speed of the plane in still air is 65 miles an hour;the speed of the wind is 20 miles an hour
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第1个回答 2016-02-18
设飞机的静风航速为x,风速为y
则x+y=765/9,x-y=765/17,
解得x=65,y=20
则x+y=765/9,x-y=765/17,
解得x=65,y=20