如题所述
#include <stdio.h>
int main() {
int plus = 0,negative = 0,num;
while(1) {
printf("请输入 : ");
scanf("%d",&num);
if(num == 0) break;
if(num > 0) plus++;
else negative++;
}
printf("大于0的数是%d个\n",plus);
printf("小于0的数是%d个\n\n",negative);
return 0;
}
温馨提示：答案为网友推荐，仅供参考
第1个回答 推荐于2017-07-11
#include<stdio.h>
void main()
{
int a[100] = {0}, i = 0, z=0, f=0, s;
printf("输入一个整数按回车进行下次输入\n");
while (1)
{
scanf("%d",&a[i]);
if (a[i] == 0) { break; }
i++;
}
for (s = 0; s < i; s++)
{
if (a[s] < 0) { f = f + 1; }
if (a[s] > 0) { z = z + 1; }
}
printf("正数的个数有%d个\n负数的个数有%d个\n", z, f);
while (1);
}本回答被网友采纳
void main()
{
int a[100] = {0}, i = 0, z=0, f=0, s;
printf("输入一个整数按回车进行下次输入\n");
while (1)
{
scanf("%d",&a[i]);
if (a[i] == 0) { break; }
i++;
}
for (s = 0; s < i; s++)
{
if (a[s] < 0) { f = f + 1; }
if (a[s] > 0) { z = z + 1; }
}
printf("正数的个数有%d个\n负数的个数有%d个\n", z, f);
while (1);
}本回答被网友采纳
