1.（1-a²)(1-b²)-4ab 2.2x²+xy-6y²+2x+11y-4 3.x³-y³-x²-xy-y² 4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc 5.a²(b-c)＋b²(c-a)+c²(a-b) 6.﹙ab+bc+ca)(a+b+c)-abc 7.x^4+(x+y)^4+y^4 8.x³-19x-30 9.x³+6x²+11x+6 10.2x^4--5x³－10x²+15x=18
楼上趁我修正错误抄袭。。严重BS！！
不过你抄袭的是错误的，我的是正解！1
1.（1-a²)(1-b²)-4ab
=1-b²-a²+a²b²-4ab
=1-(a+b)²+(ab)²-2ab
=(ab-1)²-(a+b)²
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
=(x-y)(x²+xy+y²)-(x²+xy+y²)
=(x-y-1)(x²+xy+y²)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(ab²+a²b+abc)+(bc²+b²c+abc)+(ca²+c²a)
=ab(a+b+c)+bc(a+b+c)+ac(a+c)
=(a+b+c)(ab+bc)+ac(a+c)
=b(a+b+c)(a+c)+ac(a+c)
=(a+c)[b(a+b+c)+ac]
5.a²(b-c)＋b²(c-a)+c²(a-b)
=a²b-ca²+c²a-b²a+b²c-c²b
=（b-c）a²+（c²-b²）a+bc（b-c）
=（b-c）[a²-（b+c）a+bc]
=（b-c）（a-b）（a-c）
6.﹙ab+bc+ca)(a+b+c)-abc
=a²b+2abc+ca²+ab²+b²c+bc²+c²a
=(a²b+ab²)+(bc²+ac²)+(2cab+ca²+cb²)
=ab(a+b)+c²(a+b)+c(a+b)²
=(a+b)(ab+c²+ac+cb)
=(a+b)[(ab+bc)+(c²+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=x^4+y^4+[(x²+y²)+2xy]²
=x^4+y^4+(x²+y²)²+4xy(x²+y²)+4x²y²
=(x^4+2x²y²+y^4)+(x²+y²)²+4xy(x²+y²)+2x²y²
=2(x²+y²)²+4xy(x²+y²)+2x²y²
=2[(x²+y²)²+2xy(x²+y²)+x²y²]
=2(x²+y²+xy)²
8.x³-19x-30
=x³-9x-10x-30
=x(x²-9)-(10x+30)
=x(x+3)(x-3)-10(x+3)
=(x+3)(x(x-3)-10)
=(x+3)(x²-3x-10)
=(x+3)(x-5)(x+2)
9.x³+6x²+11x+6
=﹙x²+6x+8﹚x+3x+6
=﹙x+2﹚﹙x+4﹚x+3﹙x+2﹚
=﹙x+2﹚[﹙x+4﹚x+3]
=﹙x+2﹚﹙x²+4x+3﹚
=﹙x+2﹚﹙x+1﹚﹙x+3﹚
10.2x^4-5x³－10x²+15x+18
=x³(2x+3)-8x³-10x²+15x+18
=x³(2x+3)-4x²(2x+3)+2x²+15x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+12x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+6(2x+3)
=(2x+3)(x³-4x²+x+6)
=(2x+3)[x³-3x²-(x²-3x)-2x+6]
=(2x+3)[x²(x-3)-x(x-3)-2(x-3) ]
=(2x+3)(x-3)(x²-x-2)
=(2x+3)(x-3)(x-2)(x+1)
不过你抄袭的是错误的，我的是正解！1
1.（1-a²)(1-b²)-4ab
=1-b²-a²+a²b²-4ab
=1-(a+b)²+(ab)²-2ab
=(ab-1)²-(a+b)²
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
=(x-y)(x²+xy+y²)-(x²+xy+y²)
=(x-y-1)(x²+xy+y²)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(ab²+a²b+abc)+(bc²+b²c+abc)+(ca²+c²a)
=ab(a+b+c)+bc(a+b+c)+ac(a+c)
=(a+b+c)(ab+bc)+ac(a+c)
=b(a+b+c)(a+c)+ac(a+c)
=(a+c)[b(a+b+c)+ac]
5.a²(b-c)＋b²(c-a)+c²(a-b)
=a²b-ca²+c²a-b²a+b²c-c²b
=（b-c）a²+（c²-b²）a+bc（b-c）
=（b-c）[a²-（b+c）a+bc]
=（b-c）（a-b）（a-c）
6.﹙ab+bc+ca)(a+b+c)-abc
=a²b+2abc+ca²+ab²+b²c+bc²+c²a
=(a²b+ab²)+(bc²+ac²)+(2cab+ca²+cb²)
=ab(a+b)+c²(a+b)+c(a+b)²
=(a+b)(ab+c²+ac+cb)
=(a+b)[(ab+bc)+(c²+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=x^4+y^4+[(x²+y²)+2xy]²
=x^4+y^4+(x²+y²)²+4xy(x²+y²)+4x²y²
=(x^4+2x²y²+y^4)+(x²+y²)²+4xy(x²+y²)+2x²y²
=2(x²+y²)²+4xy(x²+y²)+2x²y²
=2[(x²+y²)²+2xy(x²+y²)+x²y²]
=2(x²+y²+xy)²
8.x³-19x-30
=x³-9x-10x-30
=x(x²-9)-(10x+30)
=x(x+3)(x-3)-10(x+3)
=(x+3)(x(x-3)-10)
=(x+3)(x²-3x-10)
=(x+3)(x-5)(x+2)
9.x³+6x²+11x+6
=﹙x²+6x+8﹚x+3x+6
=﹙x+2﹚﹙x+4﹚x+3﹙x+2﹚
=﹙x+2﹚[﹙x+4﹚x+3]
=﹙x+2﹚﹙x²+4x+3﹚
=﹙x+2﹚﹙x+1﹚﹙x+3﹚
10.2x^4-5x³－10x²+15x+18
=x³(2x+3)-8x³-10x²+15x+18
=x³(2x+3)-4x²(2x+3)+2x²+15x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+12x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+6(2x+3)
=(2x+3)(x³-4x²+x+6)
=(2x+3)[x³-3x²-(x²-3x)-2x+6]
=(2x+3)[x²(x-3)-x(x-3)-2(x-3) ]
=(2x+3)(x-3)(x²-x-2)
=(2x+3)(x-3)(x-2)(x+1)
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第1个回答 2011-09-01
1.（1-a²)(1-b²)-4ab
=1-b²-a²+a²b²-4ab
=1-(a+b)²+(ab)²-2ab
=(ab-1)²-(a+b)²
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
=(x-y)(x²+xy+y²)-(x²+xy+y²)
=(x-y-1)(x²+xy+y²)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(ab²+a²b+abc)+(bc²+b²c+abc)+(ca²+c²a)
=ab(a+b+c)+bc(a+b+c)+ac(a+c)
=(a+b+c)(ab+bc)+ac(a+c)
=b(a+b+c)(a+c)+ac(a+c)
=(a+c)[b(a+b+c)+ac]
5.a²(b-c)＋b²(c-a)+c²(a-b)
=a²b-ca²+c²a-b²a+b²c-c²b
=（b-c）a²+（c²-b²）a+bc（b-c）
=（b-c）[a²-（b+c）a+bc]
=（b-c）（a-b）（a-c）
6.﹙ab+bc+ca)(a+b+c)-abc
=a²b+2abc+ca²+ab²+b²c+bc²+c²a
=(a²b+ab²)+(bc²+ac²)+(2cab+ca²+cb²)
=ab(a+b)+c²(a+b)+c(a+b)²
=(a+b)(ab+c²+ac+cb)
=(a+b)[(ab+bc)+(c²+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=x^4+y^4+[(x²+y²)+2xy]²
=x^4+y^4+(x²+y²)²+4xy(x²+y²)+4x²y²
=(x^4+2x²y²+y^4)+(x²+y²)²+4xy(x²+y²)+2x²y²
=2(x²+y²)²+4xy(x²+y²)+2x²y²
=2[(x²+y²)²+2xy(x²+y²)+x²y²]
=2(x²+y²+xy)²
8.x³-19x-30
=x^3-9x-10x-30
=x(x²-9)-(10x+30)
=x(x+3)(x-3)-10(x+3)
=(x+3)(x(x-3)-10)
=(x+3)(x²-3x-10)
=(x+3)(x-5)(x+2)
9.x³+6x²+11x+6
=﹙x²+6x+8﹚x+3x+6
=﹙x+2﹚﹙x+4﹚x+3﹙x+2﹚
=﹙x+2﹚[﹙x+4﹚x+3]
=﹙x+2﹚﹙x²+4x+3﹚
=﹙x+2﹚﹙x+1﹚﹙x+3﹚
10.2x^4-5x³－10x²+15x+18
=x³(2x+3)-8x³-10x²+15x+18
=x³(2x+3)-4x²(2x+3)+2x²+15x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+12x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+6(2x+3)
=(2x+3)(x³-4x²+x+6)
反分解就出来了
=1-b²-a²+a²b²-4ab
=1-(a+b)²+(ab)²-2ab
=(ab-1)²-(a+b)²
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
=(x-y)(x²+xy+y²)-(x²+xy+y²)
=(x-y-1)(x²+xy+y²)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(ab²+a²b+abc)+(bc²+b²c+abc)+(ca²+c²a)
=ab(a+b+c)+bc(a+b+c)+ac(a+c)
=(a+b+c)(ab+bc)+ac(a+c)
=b(a+b+c)(a+c)+ac(a+c)
=(a+c)[b(a+b+c)+ac]
5.a²(b-c)＋b²(c-a)+c²(a-b)
=a²b-ca²+c²a-b²a+b²c-c²b
=（b-c）a²+（c²-b²）a+bc（b-c）
=（b-c）[a²-（b+c）a+bc]
=（b-c）（a-b）（a-c）
6.﹙ab+bc+ca)(a+b+c)-abc
=a²b+2abc+ca²+ab²+b²c+bc²+c²a
=(a²b+ab²)+(bc²+ac²)+(2cab+ca²+cb²)
=ab(a+b)+c²(a+b)+c(a+b)²
=(a+b)(ab+c²+ac+cb)
=(a+b)[(ab+bc)+(c²+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=x^4+y^4+[(x²+y²)+2xy]²
=x^4+y^4+(x²+y²)²+4xy(x²+y²)+4x²y²
=(x^4+2x²y²+y^4)+(x²+y²)²+4xy(x²+y²)+2x²y²
=2(x²+y²)²+4xy(x²+y²)+2x²y²
=2[(x²+y²)²+2xy(x²+y²)+x²y²]
=2(x²+y²+xy)²
8.x³-19x-30
=x^3-9x-10x-30
=x(x²-9)-(10x+30)
=x(x+3)(x-3)-10(x+3)
=(x+3)(x(x-3)-10)
=(x+3)(x²-3x-10)
=(x+3)(x-5)(x+2)
9.x³+6x²+11x+6
=﹙x²+6x+8﹚x+3x+6
=﹙x+2﹚﹙x+4﹚x+3﹙x+2﹚
=﹙x+2﹚[﹙x+4﹚x+3]
=﹙x+2﹚﹙x²+4x+3﹚
=﹙x+2﹚﹙x+1﹚﹙x+3﹚
10.2x^4-5x³－10x²+15x+18
=x³(2x+3)-8x³-10x²+15x+18
=x³(2x+3)-4x²(2x+3)+2x²+15x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+12x+18
=x³(2x+3)-4x²(2x+3)+x(2x+3)+6(2x+3)
=(2x+3)(x³-4x²+x+6)
反分解就出来了
第2个回答 2011-09-01
1.（1-a²)(1-b²)-4ab
=a^2*b^2-a^2-b^2+1-4ab
=(a^2*b^2-2ab+1)-(a^2+b^2+2ab)
=(ab-1)^2-(a+b)^2
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
5.a²(b-c)＋b²(c-a)+c²(a-b)
=(a^2b-b^2a)-(a^2c-b^2c)+c^2(a-b)
=ab(a-b)-c(a-b)(a+b)+c^2(a-b)
=(a-b)(ab-c(a+b)+c^2)
=(a-b)(ab-ac-bc+c^2)
=(a-b)(a(b-c)-c(b-c))
=(a-b)(b-c)(a-c)
6.﹙ab+bc+ca)(a+b+c)-abc
=a^2b+2abc+ca^2+ab^2+b^2c+bc^2+c^2a
=(a^2b+ab^2)+(bc^2+ac^2)+(2cab+ca^2+cb^2)
=ab(a+b)+c^2(a+b)+c(a+b)^2
=(a+b)(ab+c^2+ac+cb)
=(a+b)[(ab+bc)+(c^2+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=(x^2+y^2)^2-2x^2y^2+(x+y)^4
=[(x+y)^2-2xy]^2-2x^2y^2+(x+y)^4
=[(x+y)^2]^2-4xy(x+y)^2+4x^2y^2-2x^2y^2+(x+y)^4
=2(x+y)^4-4xy(x+y)^2+2x^2y^2
=2[(x+y)^4-2xy(x+y)^2+(xy)^2]
=2[(x+y)^2-xy]^2
=2(x^2+xy+y^2)^2.
8.x³-19x-30
9.x³+6x²+11x+6
10.2x^4--5x³－10x²+15x=18
吃饭去了，尽量了，立刻能写出来的只能这么多了本回答被提问者采纳
=a^2*b^2-a^2-b^2+1-4ab
=(a^2*b^2-2ab+1)-(a^2+b^2+2ab)
=(ab-1)^2-(a+b)^2
=(ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+2y)+2x+11y-4
=(2x-3y)(x+2y)+4x+8y-2x+3y-4
=(2x-3y)(x+2y)+4(x+2y)-2x+3y-4
=(x+2y)(2x-3y+4)-(2x-3y+4)
=(2x-3y+4)(x+2y-1)
3.x³-y³-x²-xy-y²
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
5.a²(b-c)＋b²(c-a)+c²(a-b)
=(a^2b-b^2a)-(a^2c-b^2c)+c^2(a-b)
=ab(a-b)-c(a-b)(a+b)+c^2(a-b)
=(a-b)(ab-c(a+b)+c^2)
=(a-b)(ab-ac-bc+c^2)
=(a-b)(a(b-c)-c(b-c))
=(a-b)(b-c)(a-c)
6.﹙ab+bc+ca)(a+b+c)-abc
=a^2b+2abc+ca^2+ab^2+b^2c+bc^2+c^2a
=(a^2b+ab^2)+(bc^2+ac^2)+(2cab+ca^2+cb^2)
=ab(a+b)+c^2(a+b)+c(a+b)^2
=(a+b)(ab+c^2+ac+cb)
=(a+b)[(ab+bc)+(c^2+ac)]
=(a+b)(a+c)(b+c)
7.x^4+(x+y)^4+y^4
=(x^2+y^2)^2-2x^2y^2+(x+y)^4
=[(x+y)^2-2xy]^2-2x^2y^2+(x+y)^4
=[(x+y)^2]^2-4xy(x+y)^2+4x^2y^2-2x^2y^2+(x+y)^4
=2(x+y)^4-4xy(x+y)^2+2x^2y^2
=2[(x+y)^4-2xy(x+y)^2+(xy)^2]
=2[(x+y)^2-xy]^2
=2(x^2+xy+y^2)^2.
8.x³-19x-30
9.x³+6x²+11x+6
10.2x^4--5x³－10x²+15x=18
吃饭去了，尽量了，立刻能写出来的只能这么多了本回答被提问者采纳
第3个回答 2011-09-01
1、 原式=1-a^2-b^2+a^2b^2-4ab=(ab-1)^2-(a+b)^2=(ab-1+a+b)(ab-1-a-b)
2、
3、 原式=(x-y)（x^2+xy+y^2）-( x^2+xy+y^2)= （x^2+xy+y^2）(x-y-1)
4、 原式=ab(a+b)+c(a+b)^2+ac^2+bc^2=(a+b)(ab+ac+bc)+c^2(a+b)= (a+b)( ab+ac+bc+c^2)
5、 原式=a^2(b-c)+bc(b-c)-a(b^2-c^2)=(b-c)(a^2+bc-ab-ac)=( b-c)(a-b)(a-c)
6、 同4
7、 原式=（x^2+y^2）^2-2x^2y^2+（x^2+y^2）^4=（x^2+y^2）^2+（x^2+y^2）^2+4xy（x^2+y^2）+2x^2y^2=2（x^2+y^2）^2+4xy（x^2+y^2）+2x^2y^2=2(x^2+y^2+xy)^2
8、 X=5是该式子=0的解之一，原式=（x-5）(x^2+5x+6)= （x-5）(x+2)(x+3)
9、 X=-1是该式子=0的解之一,原式=（x+1）(x^2+5x+6)= （x+1）(x+2)(x+3)
2、
3、 原式=(x-y)（x^2+xy+y^2）-( x^2+xy+y^2)= （x^2+xy+y^2）(x-y-1)
4、 原式=ab(a+b)+c(a+b)^2+ac^2+bc^2=(a+b)(ab+ac+bc)+c^2(a+b)= (a+b)( ab+ac+bc+c^2)
5、 原式=a^2(b-c)+bc(b-c)-a(b^2-c^2)=(b-c)(a^2+bc-ab-ac)=( b-c)(a-b)(a-c)
6、 同4
7、 原式=（x^2+y^2）^2-2x^2y^2+（x^2+y^2）^4=（x^2+y^2）^2+（x^2+y^2）^2+4xy（x^2+y^2）+2x^2y^2=2（x^2+y^2）^2+4xy（x^2+y^2）+2x^2y^2=2(x^2+y^2+xy)^2
8、 X=5是该式子=0的解之一，原式=（x-5）(x^2+5x+6)= （x-5）(x+2)(x+3)
9、 X=-1是该式子=0的解之一,原式=（x+1）(x^2+5x+6)= （x+1）(x+2)(x+3)
第4个回答 2011-09-01
1.（1-a²)(1-b²)-4ab
=（ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+y)+2x+11y-4
3.x³-y³-x²-xy-y²
=(x²+xy+y²)(x-y-1)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(b+c)(ab+ac+a^2+c)
5.a²(b-c)＋b²(c-a)+c²(a-b)
=
没有时间啦
6.﹙ab+bc+ca)(a+b+c)-abc 7.x^4+(x+y)^4+y^4 8.x³-19x-30 9.x³+6x²+11x+6 10.2x^4--5x³－10x²+15x=18
=（ab-1+a+b)(ab-1-a-b)
2.2x²+xy-6y²+2x+11y-4
=(2x-3y)(x+y)+2x+11y-4
3.x³-y³-x²-xy-y²
=(x²+xy+y²)(x-y-1)
4.a²b﹢ab²﹢a²c﹢ac²﹢b²c﹢bc²﹢2abc
=(b+c)(ab+ac+a^2+c)
5.a²(b-c)＋b²(c-a)+c²(a-b)
=
没有时间啦
6.﹙ab+bc+ca)(a+b+c)-abc 7.x^4+(x+y)^4+y^4 8.x³-19x-30 9.x³+6x²+11x+6 10.2x^4--5x³－10x²+15x=18
