a向量+b向量+c向量=0,a向量*b向量=b向量*c向量=c向量*a向量=-1,

O,A,B,C,为平面上4个点,OA向量=a向量,OB向量=b向量,OC向量=c向量,求|a向量|+|b向量|+|c向量|

第1个回答  2011-09-16
a+b+c=0,a*b=b*c=c*a=-1,
所以a=-(b+c)
从而a*a=-a*(b+c)=-ab-ac=2,
即a^2=2,
∴|a|=√2

b*b=-b*(a+c)=-ab-bc=2,
即b^2=2,
∴|b|=√2

同理|c|=√2
所以,|a|+|b|+|c|=3√2本回答被提问者采纳
第2个回答  2011-09-16
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