用C# 用户从键盘输入月份,使用switch语句输出该月份的天数

如题所述

给你个控制台的代码吧,很简单的

Console.WriteLine("请输入年份:");

            string a = Console.ReadLine();

            Console.WriteLine("请输入月份数字:");

            string b=Console.ReadLine();

            string c = "";

            if (b == "2")

            {

                c = (Convert.ToInt32(a) % 4 == 0) ? (b + "闰年") : (b + "非闰年");

            }

            else

                c = b;

                switch (c)

                {

                    case "1":

                        Console.WriteLine("31天");

                        break;

                    case "2闰年":

                        Console.WriteLine("29天");

                        break;

                    case "2非闰年":

                        Console.WriteLine("28天");

                        break;

                    case "3":

                        Console.WriteLine("31天");

                        break;

                    case "4":

                        Console.WriteLine("30天");

                        break;

                    case "5":

                        Console.WriteLine("31天");

                        break;

                    case "6":

                        Console.WriteLine("30天");

                        break;

                    case "7":

                        Console.WriteLine("31天");

                        break;

                    case "8":

                        Console.WriteLine("31天");

                        break;

                    case "9":

                        Console.WriteLine("30天");

                        break;

                    case "10":

                        Console.WriteLine("31天");

                        break;

                    case "11":

                        Console.WriteLine("30天");

                        break;

                    case "12":

                        Console.WriteLine("31天");

                        break;

                }

            Console.ReadKey();

温馨提示:答案为网友推荐,仅供参考
第1个回答  推荐于2017-11-23
我这个保证你满意,你试试看呀!
Console.WriteLine("输入一个月份:");
int year = int.Parse(Console.ReadLine());
string month = Console.ReadLine();
switch (month)
{
case "1":
case "3":
case "5":
case "7":
case "8":
case "10":
case "12":
Console.WriteLine("31天");
break;
case "4":
case "6":
case "9":
case "11":
Console.WriteLine("是30天");
break;
case "2":
if (year % 400 == 0 || year % 4 == 0 && year % 100 != 0)
{
Console.WriteLine("29天");
}
else
{
Console.WriteLine("28天");
}
break;
default:
Console.WriteLine("错误");
break;
}本回答被提问者采纳
第2个回答  2010-09-20
int mouth;
Console.WriteLine("输入月份:");
mouth=Convert.ToInt16(Console.ReadLine());
if(mounth<=12&&mouth>0){
switch(mounth)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
Console.WriteLine("{0}月有31天",mouth);
break;
case 2:
Console.WriteLine("2月闰年29天,平年28天");
break;
default:
Console.WriteLine("{0}月有30天",mouth);
}
}
else
{
Console.WriteLine("月份输入有误!");
}

Console.ReadLine();
行不?要是动态判断闰年平年的话,告诉你一下,年份能被4整除但不能被100整除或能被400整除的为润年

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