把题目的过程答案写给我。算式分别是、(x+2y)二次方 (ax+b)(cx+d) (x+y)(a+2b) (2a+3)(二分之三b+5) (2x+3)(-x-1) (-2m-1)(3m-2) (x-y)二次方 (-2x+3)二次方
(x+2y)äºæ¬¡æ¹
=xäºæ¬¡æ¹+2x2y+2yäºæ¬¡æ¹
=xäºæ¬¡æ¹+4xy+2yäºæ¬¡æ¹
ï¼ax+b)(cx+d)
=axcx+axd+bcx+bd
ac(x)äºæ¬¡æ¹+axd+bcx+bd
(x+y)(a+2b)
=xa+2xb+ya+2yb
(2a+3)(äºåä¹ä¸b+5)
=3ab+10a+äºåä¹ä¹b+15
(2x+3)(-x-1)
=-2xäºæ¬¡æ¹-5x-3
(-2 m-1)(3m-2)
=-6mäºæ¬¡æ¹+m+2
(x-y)äºæ¬¡æ¹
=xäºæ¬¡æ¹-2xy+yäºæ¬¡æ¹
(-2x+3)äºæ¬¡æ¹
=4xäºæ¬¡æ¹-12x+9
=xäºæ¬¡æ¹+2x2y+2yäºæ¬¡æ¹
=xäºæ¬¡æ¹+4xy+2yäºæ¬¡æ¹
ï¼ax+b)(cx+d)
=axcx+axd+bcx+bd
ac(x)äºæ¬¡æ¹+axd+bcx+bd
(x+y)(a+2b)
=xa+2xb+ya+2yb
(2a+3)(äºåä¹ä¸b+5)
=3ab+10a+äºåä¹ä¹b+15
(2x+3)(-x-1)
=-2xäºæ¬¡æ¹-5x-3
(-2 m-1)(3m-2)
=-6mäºæ¬¡æ¹+m+2
(x-y)äºæ¬¡æ¹
=xäºæ¬¡æ¹-2xy+yäºæ¬¡æ¹
(-2x+3)äºæ¬¡æ¹
=4xäºæ¬¡æ¹-12x+9
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第1个回答 2010-03-27
x+2y)二次方
=x二次方+2x2y+2y二次方
=x二次方+4xy+2y二次方
(ax+b)(cx+d)
=axcx+axd+bcx+bd
ac(x)二次方+axd+bcx+bd
(x+y)(a+2b)
=xa+2xb+ya+2yb
(2a+3)(二分之三b+5)
=3ab+10a+二分之九b+15
(2x+3)(-x-1)
=-2x二次方-5x-3
(-2 m-1)(3m-2)
=-6m二次方+m+2
(x-y)二次方
=x二次方-2xy+y二次方
(-2x+3)二次方
=4x二次方-12x+9
=x二次方+2x2y+2y二次方
=x二次方+4xy+2y二次方
(ax+b)(cx+d)
=axcx+axd+bcx+bd
ac(x)二次方+axd+bcx+bd
(x+y)(a+2b)
=xa+2xb+ya+2yb
(2a+3)(二分之三b+5)
=3ab+10a+二分之九b+15
(2x+3)(-x-1)
=-2x二次方-5x-3
(-2 m-1)(3m-2)
=-6m二次方+m+2
(x-y)二次方
=x二次方-2xy+y二次方
(-2x+3)二次方
=4x二次方-12x+9
第2个回答 2010-03-19
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