如题所述
for i in `ls`;do if [[ ! -s $i ]];then echo "$i æ¯ç©ºæ件";fi;done;
循ç¯æ£æµå½åç®å½ä¸çæ件æ¯å¦ä¸ºç©ºï¼å¦ææ¯ç©ºï¼æå°åºç»æã
循ç¯æ£æµå½åç®å½ä¸çæ件æ¯å¦ä¸ºç©ºï¼å¦ææ¯ç©ºï¼æå°åºç»æã
温馨提示:答案为网友推荐,仅供参考