于负四分之一,试求出a的值,并正确解出方程。
(x+1)/2 - (x-3)/6 = (5x+a)/3 + 6
å»åæ¯æ¶å³è¾¹çå 6没æä¹6:
(x+1)/2 - (x-3)/6 = (5x+a)/3 ï¼x=-1/4
(-1/4+1)/2 - (-1/4-3)/6 = (-5/4+a)/3
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(-3+12) - (-1-12) = (-10+8a)
å»æ¬å·ï¼
-3+12 +1+12 = -10+8a
22 = -10+8a
8a = 12
a = 12/8 = 3/2
(x+1)/2 - (x-3)/6 = (5x+3/2)/3 + 6
å»åæ¯æ¶å³è¾¹çå 6没æä¹6:
(x+1)/2 - (x-3)/6 = (5x+a)/3 ï¼x=-1/4
(-1/4+1)/2 - (-1/4-3)/6 = (-5/4+a)/3
å»åæ¯ï¼ä¸¤è¾¹åä¹ä»¥24ï¼ï¼
(-3+12) - (-1-12) = (-10+8a)
å»æ¬å·ï¼
-3+12 +1+12 = -10+8a
22 = -10+8a
8a = 12
a = 12/8 = 3/2
(x+1)/2 - (x-3)/6 = (5x+3/2)/3 + 6
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