编程计算由下列公式确定的S值,其中n是用户输入的正整数,注意选用合适的变量类型: (1)S=1(平方)+2(平方)+3(平方)+...+n(平方) (2)S=1*2(平方)*3(3次方)+*…*n(n次方) (3)S=1+1*2+1*2*3+…+1*2*3*…*n (4)s=1-1/3+1/5-1/7+1/9-…+(-1)(n+1次方)1/2n-1
谢谢大家了，
(1)S=1(平方)+2(平方)+3(平方)+...+n(平方)
(2)S=1*2(平方)*3(3次方)+*…*n(n次方)
(3)S=1+1*2+1*2*3+…+1*2*3*…*n
(4)s=1-1/3+1/5-1/7+1/9-…+(-1)(n+1次方)1/2n-1
(1)S=1^2+2^2+3^2+4^2+...+n^2
(2)S=1*2^2*3^3*4^4.....*n^n
(3)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+S*t
next t
(4)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+(-1)^(n+1)*1/(2n-1)
next t
(2)S=1*2(平方)*3(3次方)+*…*n(n次方)
(3)S=1+1*2+1*2*3+…+1*2*3*…*n
(4)s=1-1/3+1/5-1/7+1/9-…+(-1)(n+1次方)1/2n-1
(1)S=1^2+2^2+3^2+4^2+...+n^2
(2)S=1*2^2*3^3*4^4.....*n^n
(3)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+S*t
next t
(4)
dim n as integr,S As long
n=text1.text
S=1
for t=1 to n
S=S+(-1)^(n+1)*1/(2n-1)
next t
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第1个回答 2006-11-29
c语言版(1)#include"iostream.h"
int s=0;
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=(n+1)*(n+1);
}
printf("%d",s);
}
(2)#include"iostream.h"
int s=0;
int ndencifang(int n);
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=ndencifang(i+1);
}
printf("%d",s);
}
int ndencifang(int n)
{
int s=1
for(i=0;i<n;i++)
{
s*=n;
}
return s;
}
快断网了我先下了明天再给你发
int s=0;
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=(n+1)*(n+1);
}
printf("%d",s);
}
(2)#include"iostream.h"
int s=0;
int ndencifang(int n);
void main()
{
scanf("%d",&n);
for(int i=0;i<n;i++)
{
s+=ndencifang(i+1);
}
printf("%d",s);
}
int ndencifang(int n)
{
int s=1
for(i=0;i<n;i++)
{
s*=n;
}
return s;
}
快断网了我先下了明天再给你发
第2个回答 2006-11-29
啥语言？。。。。都不说清楚
