解方程:2x2-6x+3=0.
解法1:∵a=2,b=-6,c=3
∴x=
∴x1=
,x2=
;
解法2:x2-3x+3=?
x2-3x+
=?
+
(x?
)2=
x?
=±
∴x1=
,x2=
.
∴x=
6±
| ||
2×2 |
∴x1=
3+
| ||
2 |
3?
| ||
2 |
解法2:x2-3x+3=?
3 |
2 |
x2-3x+
9 |
4 |
3 |
2 |
9 |
4 |
(x?
3 |
2 |
3 |
4 |
x?
3 |
2 |
|
∴x1=
3+
| ||
2 |
3?
| ||
2 |
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