如题所述
1.åæ¯ä¸åï¼ååç¸å åï¼ä¸º
(2x-5+6-x-7+2x)/(x-2)^2
=3(x-2)/(x-2)^2
=3/(x-2)
2.第äºä¸ªåå¼æ个è´å·ï¼åæ¯å为ä¸æ ·çï¼ç¶åååç¸å åï¼ä¸º
(x^2-y^2-x^2-4y^2+4xy+5y^2-4xy)/(x^2-9y^2)
=0
(2x-5+6-x-7+2x)/(x-2)^2
=3(x-2)/(x-2)^2
=3/(x-2)
2.第äºä¸ªåå¼æ个è´å·ï¼åæ¯å为ä¸æ ·çï¼ç¶åååç¸å åï¼ä¸º
(x^2-y^2-x^2-4y^2+4xy+5y^2-4xy)/(x^2-9y^2)
=0
温馨提示：答案为网友推荐，仅供参考
第1个回答 推荐于2017-11-09
解：
1、原式=(2x-5)/(x-2)^2+(6-x)/(x-2)^2-(7-2x)/(x-2)^2
=(2x-5+6-x-7+2x)/(x-2)^2
=3(x-2)/(x-2)^2
=3/(x-2)
2、原式=(x^2-y^2-x^2-4y^2+4xy+5y^2-4xy)/(x^2-9y^2)
=0本回答被网友采纳
1、原式=(2x-5)/(x-2)^2+(6-x)/(x-2)^2-(7-2x)/(x-2)^2
=(2x-5+6-x-7+2x)/(x-2)^2
=3(x-2)/(x-2)^2
=3/(x-2)
2、原式=(x^2-y^2-x^2-4y^2+4xy+5y^2-4xy)/(x^2-9y^2)
=0本回答被网友采纳
