两个大人带四个孩子去坐只有六个位置的圆型旋转木马，那么两个大人不相邻的概率为：

【答案】：B
方法一：六个人坐在圆型旋转木马的情况总数为[img]https://img.shiyebian.net/gwyshijuan/633/116.png[/img]。现先让四个孩子去坐，情况数为[img]https://img.shiyebian.net/gwyshijuan/633/117.png[/img]，四个孩子之间可形成4个空，再让两个大人各选一个空，情况数为[img]https://img.shiyebian.net/gwyshijuan/633/118.png[/img]，故两个大人不相邻的情况数为[img]https://img.shiyebian.net/gwyshijuan/633/119.png[/img]，题目所求概率为[img]https://img.shiyebian.net/gwyshijuan/633/120.png[/img]。
方法二：六个人坐在圆型旋转木马的情况总数为[img]https://img.shiyebian.net/gwyshijuan/633/116.png[/img]。考虑反面，两个大人相邻情况数为[img]https://img.shiyebian.net/gwyshijuan/633/122.png[/img][img]https://img.shiyebian.net/gwyshijuan/633/123.png[/img]，题目所求概率为[img]https://img.shiyebian.net/gwyshijuan/633/124.png[/img]。
故正确答案为B。
备注：n个人随机围绕圆桌就坐，情况数为[img]https://img.shiyebian.net/gwyshijuan/633/125.png[/img]。

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