已知B、C是线段AD上两点,且AB:BC:CD=3:2:4,E、F分别是AB、CD的中点,且EF=22,求AB
要用方程要有过程
AB:BC:CD=3:2:4
设AB=3x,BC=2x,CD=4x
EF=1/2AB+BC+1/2CD
=3x/2+2x+2x
=11x/2
=22
x=4
AB=6追é®
设AB=3x,BC=2x,CD=4x
EF=1/2AB+BC+1/2CD
=3x/2+2x+2x
=11x/2
=22
x=4
AB=6追é®
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