如题所述
【答案】:因为y'=x2+100y2
即f(x,y)=x2+100y2,
因为欧拉法公式为
yn+1=yn+hf(xn,yn)
取h=0.1,x0=0,y(x0)=y0=0
f(x0,y0)=0
所以y1=y0+0.1f(x0,y0)=0
f(x1,y1)=f(0.1,0)=0.01
y2=y1+0.1f(x1,y1)=0.001
f(x2,y2)=f(0.2,0.001)=0.0401
y3=y2+hf(x2,y2)=0.00501
即f(x,y)=x2+100y2,
因为欧拉法公式为
yn+1=yn+hf(xn,yn)
取h=0.1,x0=0,y(x0)=y0=0
f(x0,y0)=0
所以y1=y0+0.1f(x0,y0)=0
f(x1,y1)=f(0.1,0)=0.01
y2=y1+0.1f(x1,y1)=0.001
f(x2,y2)=f(0.2,0.001)=0.0401
y3=y2+hf(x2,y2)=0.00501
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