如题所述
åç®ä¸å并ï¼
1ã(â3-â2)-2(â2-â3)
=â3-â2-2â2+2â3
=3â3-3â2ï¼
2ãâ12-â27
=2â3-3â3
=-â3ï¼
3ã(-1+ â5)/2+(-1-â5)/2
=ï¼»-1+â5-1-â5ï¼½/2
=-1ã
1ã(â3-â2)-2(â2-â3)
=â3-â2-2â2+2â3
=3â3-3â2ï¼
2ãâ12-â27
=2â3-3â3
=-â3ï¼
3ã(-1+ â5)/2+(-1-â5)/2
=ï¼»-1+â5-1-â5ï¼½/2
=-1ã
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