#include<stdio.h>
#define NULL 0
struct student
{
int num;
float score;
struct student *next;
}stu[3]={{234,333.3},{23,54.33},{255,23.66}};
void main()
{
struct student *head;
head=&stu[0];
stu[0].next=&stu[1];
stu[1].next=&stu[2];
stu[2].next=NULL;
while(*head)
{
printf("%d,%f",head->num,head->score);
head=head.next;
}
}
错在哪里？如何在此基础上改正？
谢谢！
#include<stdio.h>
struct student
{
int num;
double score;
struct student *next;
}stu[3]={{234,333.3,NULL},{23,54.33,NULL},{255,23.66,NULL}};
void main()
{
struct student *head;
head=&stu[0];
stu[0].next=&stu[1];
stu[1].next=&stu[2];
stu[2].next=NULL;
while(head)
{
printf("%d,%f\n",head->num,head->score);
head=head->next;
}
}
总结：1.指针最好赋值为NULL
2.while循环中*head出错，应该是判断指针是否为空，而不是判断指针所指的值！
3.head.next出错，head为指针，应该用head->next;
struct student
{
int num;
double score;
struct student *next;
}stu[3]={{234,333.3,NULL},{23,54.33,NULL},{255,23.66,NULL}};
void main()
{
struct student *head;
head=&stu[0];
stu[0].next=&stu[1];
stu[1].next=&stu[2];
stu[2].next=NULL;
while(head)
{
printf("%d,%f\n",head->num,head->score);
head=head->next;
}
}
总结：1.指针最好赋值为NULL
2.while循环中*head出错，应该是判断指针是否为空，而不是判断指针所指的值！
3.head.next出错，head为指针，应该用head->next;
温馨提示：答案为网友推荐，仅供参考
第1个回答 2009-08-04
#include<stdio.h>
struct student
{
int num;
float score;
struct student *next;
}stu[3]={{234,333.3},{23,54.33},{255,23.66}};
void main()
{
struct student *head;
head=&stu[0];
stu[0].next=&stu[1];
stu[1].next=&stu[2];
stu[2].next=NULL;
while(head!=NULL)//*head switch to head!=NULL
{
printf("%d,%f",head->num,head->score);
head=head->next;//. switch to ->
}
}
struct student
{
int num;
float score;
struct student *next;
}stu[3]={{234,333.3},{23,54.33},{255,23.66}};
void main()
{
struct student *head;
head=&stu[0];
stu[0].next=&stu[1];
stu[1].next=&stu[2];
stu[2].next=NULL;
while(head!=NULL)//*head switch to head!=NULL
{
printf("%d,%f",head->num,head->score);
head=head->next;//. switch to ->
}
}
