在javascript 中 unescape('%u4E25') escape('严') 这样就可以转
求函数getchar($n)
getchar('4E25') 输出 ‘严’ 就好了
<?php
/**
* 模拟JS里的unescape
*
* @param unknown_type $str
* @return unknown
*/
echo unescape('%u4E25');
function unescape($str) {
$str = rawurldecode($str);
preg_match_all("/(?:%u.{4})|.{4};|\d+;|.+/U",$str,$r);
$ar = $r[0];
#print_r($ar);
foreach($ar as $k=>$v) {
if(substr($v,0,2) == "%u")
$ar[$k] = iconv("UCS-2","GB2312",pack("H4",substr($v,-4)));
elseif(substr($v,0,3) == "")
$ar[$k] = iconv("UCS-2","GB2312",pack("H4",substr($v,3,-1)));
elseif(substr($v,0,2) == "") {
echo substr($v,2,-1)."
";
$ar[$k] = iconv("UCS-2","GB2312",pack("n",substr($v,2,-1)));
}
}
return join("",$ar);
}
?>
/**
* 模拟JS里的unescape
*
* @param unknown_type $str
* @return unknown
*/
echo unescape('%u4E25');
function unescape($str) {
$str = rawurldecode($str);
preg_match_all("/(?:%u.{4})|.{4};|\d+;|.+/U",$str,$r);
$ar = $r[0];
#print_r($ar);
foreach($ar as $k=>$v) {
if(substr($v,0,2) == "%u")
$ar[$k] = iconv("UCS-2","GB2312",pack("H4",substr($v,-4)));
elseif(substr($v,0,3) == "")
$ar[$k] = iconv("UCS-2","GB2312",pack("H4",substr($v,3,-1)));
elseif(substr($v,0,2) == "") {
echo substr($v,2,-1)."
";
$ar[$k] = iconv("UCS-2","GB2312",pack("n",substr($v,2,-1)));
}
}
return join("",$ar);
}
?>
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