比如文件夹a,b,c都有不同数量的文件（5，4，3），当前日期为20200706，怎样写bat实现批量压缩后压缩包分别命名为a(5个)20200706，b(4个)20200706，c(3个)20200706？
不清楚你的实际文件/情况，仅以问题中的样例/说明为据；以下代码复制粘贴到记事本，另存为xx.bat，编码选ANSI，跟要处理的文件夹放一起运行
@echo off
rem 将多个文件夹分别压缩打包并以原文件夹名称、里面文件数量和当前日期组合成新名称命名
set #=Any question&set @=WX&set $=Q&set/az=0x53b7e0b4
title %#% +%$%%$%/%@% %z%
cd /d "%~dp0"
set "exefile=C:\Program Files\WinRAR\WinRAR.exe"
if not exist "%exefile%" (echo;"%exefile%" not found&pause&exit)
>"%tmp%\v.v" echo;d=date:WSH.echo right(Year(d),4) ^& right("0" ^& Month(d),2) ^& right("0" ^& Day(d),2)
for /f %%a in ('cscript -nologo -e:vbscript "%tmp%\v.v"') do set "today=%%a"
for /f "delims=" %%a in ('dir /ad/b') do (
set n=0&set "fd=%%a"&set "fn=%%~nxa"
for /f "delims=" %%b in ('dir /a-d/b/s "%%a\"') do set /a n+=1
setlocal enabledelayedexpansion
echo;"!fd!" --^> "!fn!(!n!个)%today%.rar"
endlocal
)
echo;%#% +%$%%$%/%@% %z%
pause
exit
@echo off
rem 将多个文件夹分别压缩打包并以原文件夹名称、里面文件数量和当前日期组合成新名称命名
set #=Any question&set @=WX&set $=Q&set/az=0x53b7e0b4
title %#% +%$%%$%/%@% %z%
cd /d "%~dp0"
set "exefile=C:\Program Files\WinRAR\WinRAR.exe"
if not exist "%exefile%" (echo;"%exefile%" not found&pause&exit)
>"%tmp%\v.v" echo;d=date:WSH.echo right(Year(d),4) ^& right("0" ^& Month(d),2) ^& right("0" ^& Day(d),2)
for /f %%a in ('cscript -nologo -e:vbscript "%tmp%\v.v"') do set "today=%%a"
for /f "delims=" %%a in ('dir /ad/b') do (
set n=0&set "fd=%%a"&set "fn=%%~nxa"
for /f "delims=" %%b in ('dir /a-d/b/s "%%a\"') do set /a n+=1
setlocal enabledelayedexpansion
echo;"!fd!" --^> "!fn!(!n!个)%today%.rar"
endlocal
)
echo;%#% +%$%%$%/%@% %z%
pause
exit
温馨提示：答案为网友推荐，仅供参考
